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Option Prices: numerical approach Lecture 4

Option Prices: numerical approach Lecture 4

Pricing: 1.Binomial Trees

Binomial Trees

Binomial trees are frequently used to approximate the movements in the price of a stock or other asset In each small interval of time the stock price is assumed to move up by a proportional amount u or to move down by a proportional amount d

A Simple Binomial Model

Stock Price = $22 Stock Price = $18 Stock price = $20 probabilities can’t be 50%-50%, unless you are risk-neutral A stock price is currently $20 In three months it will be either $22 or $18

A Call Option

Stock Price = $22 Option Price = $1 Stock Price = $18 Option Price = $0 Stock price = $20 Option Price=? if you were risk-neutral (and r=0), you could say that the option is worth: 0.5=50%*1$+50%*$0 A 3-month call option on the stock has a strike price of 21.

18 22 20 U(18) U(22) U(20) Expcted U (50% prob) prob(22) has to be > prob (18), because otherwise Utility function is linear Then, in order to know prob we need to know the Utility function. But this is an impossible task, and we have to find a shortcut .... i.e. we have to find a way of “linearizing” the world

Setting Up a Riskless Portfolio

22D – 1 18D Consider the Portfolio: long D shares short 1 call option Portfolio is riskless when 22D – 1 = 18D or D = 0.25

Valuing the Portfolio

risk-fre rate=12% p.a. ---> 3% quarterly ---> disc. factor=exp(-0.12*0.25)=0.970446 The riskless portfolio is: long 0.25 shares short 1 call option The value of the portfolio in 3 months is 22´0.25 – 1 = 4.50 Note that this pay-off is deterministic, so its PV is obtained by simple discounting

Valuing the Option

The value of the portfolio today is 4.5e – 0.12´0.25 = 4.3670 The portfolio that is long 0.25 shares short 1 option is worth 4.367 The value of the shares is 5.000 (= 0.25´20 ) The value of the option is therefore 0.633 (= 5.000 – 4.367 )

Valuing the Option

note that the value of the option has been obtained without knowing the shape of the utility function but if the solution is independent of preferences functional form, then it is valid also for all utility function Then, it is valid also for risk-neutral preferences ..... ... eureka !!! let’s imagine a risk-neutral world ---> derive risk-neutral probabilities

Summing up ... Movements in Time Dt

Su Sd S p 1 – p

Risk-neutral Evaluation

Su = 22 ƒu = 1 Sd = 18 ƒd = 0 S ƒ p (1 – p ) hyp: risk-free rate=12% p.a.; t = 3m Since p is a risk-neutral probability 20e0.12 ´0.25 = 22p + 18(1 – p ); p = 0.6523 p is called the risk-neutral probability show simple_example.xls

Tree Parameters for a Nondividend Paying Stock

We choose the tree parameters p, u, and d so that the tree gives correct values for the mean & standard deviation of the stock price changes in a risk-neutral world er Dt = pu + (1– p )d s2Dt = pu 2 + (1– p )d 2 – [pu + (1– p )d ]2 A further condition often imposed is u = 1/ d

Tree Parameters for a Nondividend Paying Stock

When Dt is small a solution to the equations is

The Complete Tree

S0 S0u S0d S0 S0 S0u 2 S0d 2 S0u 2 S0u 3 S0u 4 S0d 2 S0u S0d S0d 4 S0d 3

Backwards Induction

We know the value of the option at the final nodes We work back through the tree using risk-neutral valuation to calculate the value of the option at each node, testing for early exercise when appropriate

Valuing the Option

Su = 22 ƒu = 1 Sd = 18 ƒd = 0 S ƒ 0.6523 0.3477 The value of the option is e–0.12´0.25 [0.6523´1 + 0.3477´0] = 0.633

A Two-Step Example

20 22 18 24.2 19.8 16.2 Each time step is 3 months

Valuing a Call Option

20 1.2823 22 18 24.2 3.2 19.8 0.0 16.2 0.0 2.0257 0.0 A B C D E F Value at node B = e–0.12´0.25(0.6523´3.2 + 0.3477´0) = 2.0257 Value at node C =0 Value at node A = e–0.12´0.25(0.6523´2.0257 + 0.3477´0) = 1.2823

Pricing: 2.Monte Carlo

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lezioni_castellanza_n4
Author: 
John C. Hull
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Option Prices: numerical approach Lecture 4
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Chapter 1 | option | valu | price | stock | risk | neutral | tree | portfolio
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5/22/1997 12:24:16 AM
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