Main MemoryBecause computers operate by storing numbers as bit patterns, the address itself is also represented as a bit pattern
Memory addresses are defined using unsigned binary integers
Foundations of Computer Science (計算機概論) Chapter 5
Computer Organization (計算機組織)
Outline
5.1 Central Processing Unit (CPU)
中央處理單元 5.2 Main Memory
(主記憶體) 5.3 Input/Output
(輸入/輸出)
Outline
5.4 Subsystem Interconnection
(子系統之互連) 5.5 Program Execution
(程式之執行) 5.6 Two Different Architectures
(兩種不同的架構)
Computer Hardware (Subsystems)
A computer has three subsystems: the CPU, main memory, and the input/output subsystem.
5.1
Central Processing
Unit (CPU)
(中央處理器)
CPU
The CPU performs operations on data and has an ALU (算術邏輯單元), a control unit (控制單元), and a set of registers (暫存器).
The ALU performs arithmetic (算術) and logical (邏輯) operations
The registers are stand-alone (獨立的) storage devices that hold data temporarily
Registers can hold data (資料), instructions (指令), and also function as a program counter (程式計數器)
The control unit oversees (管理) operations in a computer
5.2
Main Memory
(主記憶體)
Main Memory
Memory units Unit ------------
kilobyte
megabyte
gigabyte
terabyte
petabyte
exabyte Exact Number of bytes ------------------------
210 bytes
220 bytes
230 bytes
240 bytes
250 bytes
260 bytes Approximation ------------
103 bytes
106 bytes
109 bytes
1012 bytes
1015 bytes
1018 bytes Main memory is a collection (大量) of storage locations
The total number of uniquely (唯一) identifiable (可識別) locations in memory is called the address space (位址空間)
Main Memory
Because computers operate by storing numbers as bit patterns, the address itself is also represented as a bit pattern
Memory addresses are defined using unsigned binary integers
Example
A computer has 32 MB (megabytes) of memory. How many bits are needed to address any single byte in memory? Solution The memory address space is 32 MB, or 225 (25 x 220). This means you need log2 225 or 25 bits, to address each byte.
Example
A computer has 128 MB of memory. Each word in this computer is 8 bytes. How many bits are needed to address any single word in memory? Solution The memory address space is 128 MB, which means 227 (27 x 220). However, each word is 8 (23) bytes, which means that you have 224 words. This means you need log2 224 or 24 bits, to address each word.
Memory Types
Two types of memory are available: RAM and ROM
RAM provides the bulk (大量) of the memory in a computer, can be read from and written to by the user
SRAM uses the traditional flip-flop gates (正反閘) to hold data, and DRAM uses capacitors (電容器)
The contents of ROM come from the manufacturer (製造者); users are only allowed to read from it, but not write to it
Memory Types
Computers need
high-speed memory for registers (暫存器)
medium-speed memory for cache memory (快取記憶體
low-speed memory for main memory (主記憶體)
Cache
Cache memory is placed between the CPU and main memory. At any time contains a copy of a portion of main memory
80-20rule: It has been observed that most computers typically spend 80% of the time accessing only 20% of the data. In other words, the same data are accessed over and over again
5.3
Input/Output
(輸入/輸出)
Input/Output
The input/output subsystem is a collection (大量) of devices that allows a computer to communicate with the outside world. These devices are either nonstorage (非儲存性) devices or storage (儲存性) devices
The keyboard, monitor, and printer are examples of nonstorage devices
A magnetic disk (磁碟) is a storage device
Magnetic (磁性) Storage Device
Magnetic disk (磁碟)
Magnetic tap (磁帶)
Magnetic Disk
A magnetic disk (磁碟) is a storage device with each disk in the stack divided into tracks (磁軌) and sectors (磁區)
Physical Layout of a Magnetic Disk
Surface Organization of a Disk
Performance:
access time (存取時間) = seek time (搜尋時間) + rotational time (轉動時間) + transfer time (轉移時間)
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